What is the vertex of $y= 3x^2-9x+27$ ?

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Answer 1 · 2016-01-18T23:43:38

$Vertex (3/2, 81/4)$

x-coordinate of vertex:
$x = -b/(2a) = 9/6 = 3/2$
y-coordinate of vertex:
$y(3/2) = 3(9/4) - 9(3/2) + 27 = -27/4 + 108/4 = 81/4$

$Vertex (3/2, 81/4)$

What is the vertex of y= 3x^2-9x+27 y= 3x^2-9x+27 ?