What is the vertex of y= 4(x-2)^2-12 ?
1 Answer
May 14, 2018
Explanation:
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
y=4(x-2)^2-12" is in vertex form"
"with "h=2" and "k=-12
rArrcolor(magenta)"vertex "=(2,-12)