Question

What is the vertex of `y= −4x^2 + 8x − 19`?

Answer 1

Vertex `(1, -15)`

Explanation:

Given-

`y=-4x^2+8x-19`

`x=(-b)/(2a)=(-8)/(2 xx(-4))=(-8)/(-8)=1`

At `x = 1`

`y=-4(1)+8(1)-19=-4+8-19=-15`

Vertex `(1, -15)`