What is the vertex of $y= -5x^2 − 3x$ ?

Question

1413 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-26T12:21:12

The vertex is $(-3/10, 9/20)$

The vertex is the maximum of this parabola: so derive it, and set the derivative to zero:

$-10x-3=0 \iff x=-3/10$ .

So, the vertex has $x$ -coordinate $-3/10$ . To find the $y$ -coordinate, simply compute

$f(-3/10)=9/20$

What is the vertex of y= -5x^2 − 3x y= -5x^2 − 3x ?