What is the vertex of $y= -x^2 + 12x +4$ ?

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Answer 1 · 2015-11-26T20:14:49

Find vertex of $y = -x^2 + 12x + 4$

Ans: Vertex (6, 40)

x-coordinate of vertex: $x = (-b)/(2a) = (-12)/-2 = 6$
y-coordinate of vertex: y = y(6) = - 36 + 72 + 4 = 40
Vertex (6, 40).

What is the vertex of y= -x^2 + 12x +4 y= -x^2 + 12x +4 ?