What is the vertex of y= x^2 - 2x - 15y=x2−2x−15? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Binayaka C. May 26, 2016 Vertex is at (1,-16)(1,−16) Explanation: y=x^2-2x-15 or y= (x-1)^2-16 y=x2−2x−15ory=(x−1)2−16 We know, equation of parabola in vertex form is y=a(x-h)^2+ky=a(x−h)2+k where (h,k)(h,k) is the vertex. So here the vertex is at (1,-16)(1,−16) graph{x^2-2x-15 [-40, 40, -20, 20]}[Ans] Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph y=x^2-2x+3y=x2−2x+3? How do you know if y=16-4x^2y=16−4x2 opens up or down? How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=04x2+16x+12=0? See all questions in Quadratic Functions and Their Graphs Impact of this question 5356 views around the world You can reuse this answer Creative Commons License