What is the vertex of $y = x^{2} - 2 x - 3$ $y=x^2 - 2x -3$ ?

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Answer 1 · 2015-12-01T09:38:28

(1,-4)

Write $y = {(x - 1)}^{2} - 4$ $y= (x-1)^2 -4$ after completing the square of x terms.

Vertex is given by x-1=0 and y= -4. Vertex is (1,-4)

What is the vertex of y=x^2 - 2x -3 y=x2−2x−3y=x^2 - 2x -3 ?