What is the vertex of y= -x^2 + 2x - 7 ? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer ali ergin Mar 31, 2017 "Vertex :"(1,-6) Explanation: "given function "y=-x^2+2x-7 "derivate the function y with respect to x and make equal to zero." (d y)/(d x) =0 d/(d x)(-x^2+2x-7)=0 -2x+2=0 -2x=-2 x=2/2 x=1 "plug x=1 in the function " y=-x^2+2x-7 y=-1^2+2*1-7 y=-1+2-7 y=-6 Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph y=x^2-2x+3? How do you know if y=16-4x^2 opens up or down? How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=0? See all questions in Quadratic Functions and Their Graphs Impact of this question 4044 views around the world You can reuse this answer Creative Commons License