What is the vertex of $y = x^{2} - 4 x + 3$ $y = x^2 − 4x + 3$ ?

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What is the vertex of $y = x^{2} - 4 x + 3$ $y = x^2 − 4x + 3$ ?

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Answer 1 · 2015-10-30T10:40:24

$(2, - 1)$ $(2,-1)$

Explanation:

First, find the axis of symmetry of the equation using $x = \frac{- b}{2 a}$ $x=(-b)/(2a)$ , where the values of $a$ $a$ and $b$ $b$ comes from $y = a x^{2} + b x + c$ $y=ax^2+bx+c$

In this case, $b = - 4$ $b = -4$ and $a = 1$ $a=1$ .

So the axis of symmetry is $x = \frac{- (- 4)}{(2) (1)}$ $x=[-(-4)]/[(2)(1)]$
$x = 2$ $x=2$

Then substitute the $x$ $x$ value into the equation to find the $y$ $y$ co-ordinate.

$y = {(2)}^{2} - 4 (2) + 3$ $y=(2)^2-4(2)+3$
$= 4 - 8 + 3$ $=4-8+3$
$= - 1$ $=-1$

So the co-ordinates of the vertex are $(2, - 1)$ $(2,-1)$

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What is the vertex of $y = x^{2} - 4 x + 3$ $y = x^2 − 4x + 3$ ?

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