What is the vertex of y=-x^2-4x-3y=−x2−4x−3?

1 Answer
Roella W.
Dec 29, 2015

(-2, 1)(−2,1)

Explanation:

Rearrange the expression into the form y = (x - a)^2 + by=(x−a)2+b. The vertex is then (a, b)(a,b). a is half the coefficient of x in the original equation.
y = -(x^2 + 4x +3)y=−(x2+4x+3)
y = -((x+2)^2 -1)y=−((x+2)2−1)
y = -(x +2)^2 + 1y=−(x+2)2+1
Vertex is (-2, 1)(−2,1)

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
2712 views around the world
You can reuse this answer
Creative Commons License