What is the vertex of y=x^2+4x - 5?

1 Answer
Feb 1, 2016

vertex at (-2,-9)

Explanation:

Often the simplest way to do this is to convert the given equation into "vertex form":
color(white)("XXX")y=(x-a)^2+b with its vertex at (a,b)

Given
color(white)("XXX")y=x^2+4x-5

Completing the square:
color(white)("XXX")y=x^2+4xcolor(blue)(+4)-5color(blue)(-4)

Re-writing as a squared binomial and simplified constant
color(white)("XXX")y=(x+2)^2-9

Modifying signs into explicit vertex form:
color(white)("XXX")y=(x-(-2))^2+(-9)

If you have access to some graphing software, it can help verify that the answer is reasonable by graphing the original equation.
graph{x^2+4x-5 [-8.91, 11.09, -9.59, 0.41]}