What is the vertex of y=x^2 +5(x-3)^2?

1 Answer
Roella W.
Dec 23, 2015

The vertex is (5/sqrt(2), -30)

Explanation:

Expand and simplify the expression first
y = x^2 +5(x^2 -6x + 9)
y = 6x^2 -30x +45
y= 3(2x^2 -10x +15)
The use completing the square to get vertex form
y = 3((sqrt(2)x -5)^2 -25 + 15)
y = 3(sqrt(2)x - 5)^2 -30
The vertex is (5/sqrt(2), -30)

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