What is the vertex of $y= x^2-5x-8$ ?

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Answer 1 · 2018-04-05T14:08:26

Vertex is $(5/2,-57/4)$

$y=x^2-5x-8$

Vertex is given by $x=-b/(2a)$ where a,b refers to $ax^2+bx+c=0$

Therefore, $x=-b/(2a)=5/(2times1)=5/2$

Sub $x=5/2$ into $y=x^2-5x-8$ to get the y-value

$y=-57/4$

Vertex is $(5/2,-57/4)$

What is the vertex of y= x^2-5x-8 y= x^2-5x-8?