What is the vertex of y= x^2 - 8x + 18 ?

1 Answer
May 8, 2018

"vertex "=(4,2)

Explanation:

"given a quadratic in "color(blue)"standard form"

•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0

"then the x-coordinate of the vertex is"

•color(white)(x)x_(color(red)"vertex")=-b/(2a)

y=x^2-8x+18" is in standard form"

"with "a=1,b=-8" and "c=18

rArrx_("vertex")=-(-8)/2=4

"substitute into the equation for y-coordinate"

y_("vertex")=4^2-(8xx4)+18=2

rArrcolor(magenta)"vertex "=(4,2)
graph{x^2-8x+18 [-10, 10, -5, 5]}