What is the vertex of $y=x^2 - 8x - 3$ ?

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Answer 1 · 2016-01-01T01:22:26

The Solution set(or vertex set) is: $S = {4,-19}$

The general formula for a quadratic function is:
$y = Ax^2 + Bx + C$

To find the vertex, we apply those formulas:
$x_(vertex) = -b/(2a)$
$y_(vertex) = - triangle/(4a)$

In this case:
$x_(vertex) = - (-8)/(2*1) = - (-4) = 4$ and
$y_(vertex) = - (b^2 -4ac)/(4*1) = - (64 - 4 * 1 * (-3))/4$
$y_(vertex) = - 76/4 = -19$

So, the Solution set(or vertex set) is: $S = {4,-19}$

What is the vertex of y=x^2 - 8x - 3 y=x^2 - 8x - 3 ?