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What is the vertex of # y= x^2 - 8x-4?

1 Answer

Dec 3, 2015

Vertex $= 4$ $=4$

Explanation:

$y = x^{2} - 8 x - 4$ $y= x^2 - 8x-4$

vertex $= \frac{- b}{2} = \frac{- (- 8)}{2} = 4$ $= (-b)/2=(-(-8))/2=4$

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