What is the vertex of y= -x^2 +9x - 8y=x2+9x8?

1 Answer
Jul 26, 2017

Vertex: (9/2,49/4)(92,494)

Explanation:

Apply the vertex formula: x=-b/(2a)x=b2a, where a=-1a=1 and b=9b=9

Thus,

x=-(9)/(2(-1))x=92(1)

x=9/2x=92

We must now find the yy-value for the vertex which we can find by substituting 9/292 for xx in the given equation y=-x^2+9x-8y=x2+9x8. So...

-(9/2)^2+9(9/2)-8(92)2+9(92)8

y=-81/4+81/2-8y=814+8128

Find the LCD of 4,24,2 and 11; that is 44

y=-81/4+(81times2)/(2times2)-(8times4)/(1times4)y=814+81×22×28×41×4

y=-81/4+162/4-32/4y=814+1624324

y=(-81+162-32)/4y=81+162324

y=49/4y=494

And so the vertex is (9/2,49/4)(92,494)