What is the vertex of # y= –x^2 +x – 12?

1 Answer
iceman
Jan 20, 2017

(1/2, -47/4)(12,−474)

Explanation:

y=-x^2+x-12y=−x2+x−12 => complete the square to convert to vertex form:
y=-(x^2-x)-12y=−(x2−x)−12
y=-(x^2-x+1/4)-12+1/4y=−(x2−x+14)−12+14
y=-(x - 1/2)^2-47/4y=−(x−12)2−474
=> in the vertex form of(x-h)^2+k(x−h)2+k where(h, k)(h,k) is the vertex:
so in this case the vertex is:
(1/2, -47/4)(12,−474)

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