What is the vertex of $y=x-2 +(x-3)^2$ ?

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Answer 1 · 2017-11-14T11:43:02

Vertex is at $(2.5,0.75)$

$y=x-2+(x-3)^2 or y=x-2+x^2-6x+9$ or

$y=x^2-5x+7 or y=(x^2-5x) +7$ or

$y={x^2-5x +(5/2)^2}-25/4 +7$ or

$y=(x-2.5)^2+3/4 or y={x-2.5)^2+0.75$

Comparing with vertex form of equation

$y = a(x-h)^2+k ; (h,k)$ being vertex we find

here $h=2.5 , k=0.75 :.$ Vertex is at $(2.5,0.75)$ .

graph{(x-2)+(x-3)^2 [-10, 10, -5, 5]} [Ans]

What is the vertex of y=x-2 +(x-3)^2y=x-2 +(x-3)^2?