Question

What is the vertex of `y= (x-3)^2-5x^2+6x-9`?

Answer 1

the vertex is `(0,0)`

Explanation:

Developing the equation
`y=(x-3)^2-5x^2+6x-9=x^2-6x+9-5x^2+6x-9`
Simplifying `y=-4x^2`
So it's a parabola and the vertex is at (0,0)
Here is the graph of the function
graph{(x-3)^2-5x^2+6x-9 [-10, 10, -5, 5]}