What is the vertex of $y = (x - 3) (4 x + 2)$ $y= (x − 3)(4x + 2)$ ?

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Answer 1 · 2018-06-17T11:33:36

Vertex is at $(1.25, - 12.25)$ $(1.25 , -12.25)$

$y = (x - 3) (4 x + 2) or y = 4 x^{2} - 10 x - 6$ $y=(x-3)(4 x+2) or y= 4 x^2 -10 x -6$

$a = 4, b = - 10, c = - 6; [y = a x^{2} + b x + c$ $a= 4 , b= -10 ,c =-6 ; [y= ax^2+bx+c$

Vertex ( x coordinate) is $v_{x} = \frac{- b}{2 a} = \frac{10}{8} = 1.25$ $v_x= (-b)/(2 a)=10/8=1.25$

Putting $x = 1.25$ $x=1.25$ in the equation we get $v_{y}$ $v_y$

Vertex ( y coordinate) is

$v_{y} = 4 \cdot {1.25}^{2} - 10 \cdot 1.25 - 6 = - 12.25$ $v_y= 4 *1.25^2-10 *1.25-6=-12.25$

Vertex is at $(1.25, - 12.25)$ $(1.25, -12.25)$

graph{y=(x-3)(4x+2) [-40, 40, -20, 20]} [Ans]

What is the vertex of y=(x−3)(4x+2)y= (x − 3)(4x + 2) ?