What is the vertex of $y= (x+5)^2-10x-25$ ?

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Answer 1 · 2017-10-22T21:37:09

Vertex (0,0)

Vertex form of equation is
$y = a(x-h)^2 + k$

$y = (x+5)^2 -10x -25$

$y = x^2 + 10x +25 -10x -25 = x^2$

$y = x^2$

$a = 1, h = 0, k = 0$

$vertex (h, k) = (0,0)$

$y = x^2$
graph{x^2 [-10, 10, -5, 5]}

What is the vertex of y= (x+5)^2-10x-25 y= (x+5)^2-10x-25 ?