What is the volume of a $40 " m"xx20 " m"xx12 " m"$ room in cubic feet?

Question

1816 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-20T08:56:34

$3.39xx10^5 " ft"^3$

First, you need the conversion factor of meters to feet:

$1 " m"=3.281 " ft"$

Next, convert each edge of the room:

length = $40 " m"xx(3.281 " ft")/(1 " m")=131 " ft"$

width = $20 " m"xx(3.281 " ft")/(1 " m")=65.6 " ft"$

height = $12 " m"xx(3.281 " ft")/(1 " m")=39.4 " ft"$

Then, find the volume:

volume = length $xx$ width $xx$ height

volume = $131 " ft"xx65.5 " ft"xx39.4 " ft" = 3.39xx10^5 " ft"^3$

What is the volume of a 40 " m"xx20 " m"xx12 " m"40 " m"xx20 " m"xx12 " m" room in cubic feet?