What is the y intercept for a line with point (6.-6) slope -7/3?

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Answer 1 · 2015-09-23T23:07:49

The y-intercept is $8$ $8$ .

$y = m x + b$ $y=mx+b$ is the slope-intercept form for a linear equation, where $m$ $m$ is the slope and $b$ $b$ is the y-intercept.

$x = 6,$ $x=6,$ $y = - 6$ $y=-6$

Substitute the known values for $x$ $x$ and $y$ $y$ , and solve for $b$ $b$ .

$- 6 = - \frac{7}{3} \cdot 6 + b =$ $-6=-7/3*6+b=$

$- 6 = - \frac{42}{3} + b$ $-6=-42/3+b$

Simplify $- \frac{42}{3}$ $-42/3$ to $- 14$ $-14$ .

$- 6 = - 14 + b$ $-6=-14+b$

Add $14$ $14$ to both sides of the equation.

$14 - 6 = b$ $14-6=b$

$8 = b$ $8=b$

Switch sides.

$b = 8$ $b=8$

The y-intercept is $8$ $8$ .

The following graph has the slope-intercept equation $y = - \frac{7}{3} x + 8$ $y=-7/3x+8$

graph{y=-7/3x+8 [-19.96, 20.04, -4.39, 15.61]}