z=(X-mu)/(SD)=(35-15)/1=20z=X−μSD=35−151=20 is the zz-score of XX itself. If you want the zz-score of a mean overline{X}=35¯¯¯X=35, the answer is z=(overline{X}-mu)/((SD)/sqrt(n))=20/(1/sqrt(204)) approx 285.7z=¯¯¯X−μSD√n=201√204≈285.7. Such high zz-scores rarely occur in real life examples.