#z=(X-mu)/(SD)=(35-15)/1=20# is the #z#-score of #X# itself. If you want the #z#-score of a mean #overline{X}=35#, the answer is #z=(overline{X}-mu)/((SD)/sqrt(n))=20/(1/sqrt(204)) approx 285.7#. Such high #z#-scores rarely occur in real life examples.