What is x if $6=7/x+x$ ?

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Answer 1 · 2018-05-03T04:01:53

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$6=7/x+x$ where $x!=0$

$7/x=6-x$

$x^2*7/x=x^2(6-x)$

$7x=6x^2-x^3$

$x^3-6x^2+7x=0$

$x(x^2-6x+7)=0$

$x=0$ or $x^2-6x+7=0$

For $x^2-6x+7=0$ , we need to use the quadratic formula

ie $x=(-b+-sqrt(b^2-4ac))/(2a)$

$x=(6+-sqrt(36-28))/(2)$

$x=(6+-2sqrt2)/2$

$x=3+-sqrt2$

BUT looking at $x=0$ , it cannot be a solution because of $7/0$

Therefore, the answer is $x=3+-sqrt2$

What is x if 6=7/x+x6=7/x+x?