What is $y = x^{2} - 16 x + 40$ $y = x^2-16x+40$ written in vertex form?

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What is $y = x^{2} - 16 x + 40$ $y = x^2-16x+40$ written in vertex form?

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Answer 1 · 2018-03-26T09:16:57

$y = {(x - 8)}^{2} - 24$ $y=(x-8)^2-24$

Explanation:

$the equation of a parabola in vertex form$ $"the equation of a parabola in "color(blue)"vertex form"$ is.

$color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))$

$"where "(h,k)" are the coordinates of the vertex and a is"$
$"a multiplier"$

$"Give the equation in "color(blue)"standard form"$

$•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0$

$"then the x-coordinate of the vertex is"$

$•color(white)(x)x_(color(red)"vertex")=-b/(2a)$

$y=x^2-16x+40" is in standard form"$

$"with "a=1,b=-16" and "c=40$

$rArrx_(color(red)"vertex")=-(-16)/2=8$

$"substitute "x=8" into the equation for y-coordinate"$

$y_(color(red)"vertex")=8^2-(16xx8)+40=-24$

$rArr(h,k)=(8,-24)$

$rArry=(x-8)^2-24larrcolor(red)"in vertex form"$

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What is $y = x^{2} - 16 x + 40$ $y = x^2-16x+40$ written in vertex form?

1 Answer

Explanation:

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What is y = x^2-16x+40y=x2−16x+40y = x^2-16x+40 written in vertex form?

1 Answer

Explanation:

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What is $y = x^{2} - 16 x + 40$ $y = x^2-16x+40$ written in vertex form?