Question

What mass of `Ca(OH)_2` is contained in 1500 mL of 0.0250M `Ca(OH)_2` solution?

Answer 1

2.778g

Explanation:

`text(Molarity)= (text(Mass of solute)) / (text(Gram molecular mass of solute) × text(Volume of solution in litres))`

`text(Mass of)` `Ca(OH)_2= (0.0250M × 74.093g/(mol) × 1.5L)`

Mass of `Ca(OH)_2` = `2.778g`