What the is the polar form of $2 = -x-5x^2y-x/y +y^2$ ?

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Answer 1 · 2017-10-15T09:12:53

$5r^3sinthetacos^2theta-r^2sin^2theta+rcostheta+2+cottheta=0$

The relation between polar coordinates $(r,theta)$ and Cartesian or rectangular coordinates $(x,y)$ is given by

$x=rcostheta$ and $y=rsintheta$

Hence, $2=-x-5x^2y-x/y+y^2$ can be written as

$2=-rcostheta-5r^2cos^2thetarsintheta-(rcostheta)/(rsintheta)+r^2sin^2theta$

or $2=-rcostheta-5r^3sinthetacos^2theta-cottheta+r^2sin^2theta$

or $5r^3sinthetacos^2theta-r^2sin^2theta+rcostheta+2+cottheta=0$

What the is the polar form of 2 = -x-5x^2y-x/y +y^2 2 = -x-5x^2y-x/y +y^2 ?