What type of non-constant function has the same average rate of change and instantaneous rate of change over all intervals and for all values of "x?" Explain.

1 Answer
May 31, 2016

Any linear function f(x) = Ax+Bf(x)=Ax+B satisfies this condition.
Any function that satisfies this condition is linear.

Explanation:

Obviously, a linear function f(x) = Ax+Bf(x)=Ax+B satisfies this condition. Its average rate of change on any interval [x_1, x_2][x1,x2] is equal to
R = [f(x_2)-f(x_1)]/(x_2-x_1) = (Ax_2+B-Ax_1-B)/(x_2-x_1)=AR=f(x2)f(x1)x2x1=Ax2+BAx1Bx2x1=A

Since this is true for any interval, instantaneous rate of change at any point x_1x1 is also equal to AA since it is a limit of average rate of change when the right end of an interval x_2x2 gets infinitely close to its left end x_1x1.

A little more interesting is to prove that this class of linear functions is the only set of functions defined for all real numbers having a property of the same rate of change on any interval as well as an instantaneous rate of change.

Here is a proof.
Let's fix two points on the X-axis: x_1x1, x_2x2 and take any other point xx.
Since the average rate of change is the same on any interval,
R = [f(x_2)-f(x_1)]/(x_2-x_1) = [f(x)-f(x_1)]/(x-x_1) R=f(x2)f(x1)x2x1=f(x)f(x1)xx1

From the above we can conclude:
R(x-x_1) = f(x)-f(x_1)R(xx1)=f(x)f(x1)
f(x) = Rx-Rx_1+f(x_1)f(x)=RxRx1+f(x1)
As we see, f(x)f(x) is a linear function, which is exactly what we wanted to prove.