Question

What type of solutions and how many solutions does the equation `41x^2-31x-52=0` have?

Answer 1

`41x^2-31x-52=0`

`=>{(a=41),(b=-31),(c=-52):}`

Let us compute its discriminant.

`D=b^2-4ac=(-31)^2-4(41)(-52)=9489>0`,

which indicates that it has two real solutions.

---

I hope that this was helpful.