What volume of water would be added to 16.5 mL of a 0.0813 M solution of sodium borate in order to get a 0.0200 M solution?

1 Answer

To solve this we'll need to apply the equation

M1V1=M2V2

V1=16.5ml
V2=?
M1=0.0813
M2=0.200

Solve the equation for V2
V2 = M1V1M2

V2 = 0.0813M.16.5ml0.0200M = 67.1ml

Please note the question asks you to find the volume that must be added. You'll need to subtract 16.5mL from 67.1 to find the answer of
50.6mL.

Here is a video which discusses how to perform dilution calculations.