Where are the critical points of sec x? Precalculus Graphs of Trigonometric Functions Graphing Trigonometric Functions with Critical Points 1 Answer 1s2s2p Mar 12, 2018 x=n180^∘ where n∈ZZ or x=(nπ)/2 where n∈ZZ Explanation: Critical points occur when d/dx[secx]=0 d/dx[secx]=secxtanx=0 secx≠0 since that would mean cosx=1/0=text(undefined) So tanx=0 x=arctan(0)=0^∘,180^∘,360^∘,⋯, n180^∘ where n∈ZZ or x=arctan(0)=0,π/2,π,⋯, (nπ)/2 where n∈ZZ Answer link Related questions Where are the critical points of tan x? Where are the critical points of cot x? Where are the critical points of csc x? What are the critical points of y=2 tan x on [0, pi^2]? See all questions in Graphing Trigonometric Functions with Critical Points Impact of this question 6370 views around the world You can reuse this answer Creative Commons License