Where does the graph of y = 3x^2 − 10x − 8 cross the x-axis?
1 Answer
May 28, 2018
Explanation:
"to find where the graph crosses the x-axis set y = 0"
3x^2-10x-8=0
"using the a-c method to factor the quadratic"
"the factors of the product "3xx-8=-24
"which sum to - 10 are - 12 and + 2"
"split the middle term using these factors"
3x^2-12x+2x-8=0larrcolor(blue)"factor by grouping"
color(red)(3x)(x-4)color(red)(+2)(x-4)=0
"take out the "color(blue)"common factor "(x-4)
(x-4)(color(red)(3x+2))=0
"equate each factor to zero and solve for x"
x-4=0rArrx=4
3x+2=0rArrx=-2/3
graph{3x^2-10x-8 [-10, 10, -5, 5]}