Where does the graph of y = 3x^2 − 10x − 8 cross the x-axis?

1 Answer
May 28, 2018

x=-2/3,x=4

Explanation:

"to find where the graph crosses the x-axis set y = 0"

3x^2-10x-8=0

"using the a-c method to factor the quadratic"

"the factors of the product "3xx-8=-24

"which sum to - 10 are - 12 and + 2"

"split the middle term using these factors"

3x^2-12x+2x-8=0larrcolor(blue)"factor by grouping"

color(red)(3x)(x-4)color(red)(+2)(x-4)=0

"take out the "color(blue)"common factor "(x-4)

(x-4)(color(red)(3x+2))=0

"equate each factor to zero and solve for x"

x-4=0rArrx=4

3x+2=0rArrx=-2/3
graph{3x^2-10x-8 [-10, 10, -5, 5]}