Which linear function includes the points (-3, 1) and (-2, 4)?

1 Answer
Dec 12, 2016

"y=3x+10

Explanation:

Linear => straight line graph type function:

" "-> y=mx+c .................Equation(1)

Let point 1 be P_1->(x_1,y_1)=(-3,1)

Let point 2 be P_2->(x_2,y_2)=(-2,4)

Substitute both these ordered pairs into equation(1) giving two new equation.
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color(blue)("Determine the gradient "m)

P_1 -> 1=m(-3)+c ................................Equation(2)
P_2->4=m(-2)+c.................................Equation(3)

Equation(3) - Equation(2)

4-1=-2m+3m

color(blue)(3=m -> m=3)

color(brown)("Check: - alternative method")

Gradient ->m = ("change in up or down")/("change in along")

m=(y_2-y_1)/(x_2-x_1) = (4-1)/(-2-(-3)) =3/1=3
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color(blue)("Determine the constant (y-intercept) "c)

P_2->4=m(-2)+c

But m=3

=>4=(3)(-2)+c

4=-6+c

color(blue)(c=10)
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color(blue)("Putting it all together")

color(blue)(y=mx+c" "->" "y=3x+10)

Tony B