Which method do you use to factor #3x(x-1)+4(x-1) #?

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Answer 1 · 2014-11-04T15:18:02

I'm not sure if this is a method, but
Distributive Property of multiplication over addition is involved.

For easier visualization, let's treat #x - 1# as one variable, say #y#

#y = x - 1#

#3x(x - 1) + 4(x - 1)#

#=> 3x(y) + 4(y)#

#=> (3x + 4)(y)#

#=> (3x + 4)(x - 1)#