Which method do you use to solve the system of equations $y = \frac{1}{4} x - 14$ $y=1/4x-14$ and $y = \frac{19}{8} x + 7$ $y=19/8x+7$ ?

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Which method do you use to solve the system of equations $y = \frac{1}{4} x - 14$ $y=1/4x-14$ and $y = \frac{19}{8} x + 7$ $y=19/8x+7$ ?

1 Answer

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Answer 1 · 2018-06-05T17:49:12

$x = - \frac{168}{17}, y = - \frac{280}{17}$ $x=-168/17,y=-280/17$

Explanation:

From both equations we get
$\frac{1}{4} x - 14 = \frac{19}{8} \cdot x + 7$ $1/4x-14=19/8*x+7$
so we get
$\frac{1}{4} x - \frac{19}{8} x = 21$ $1/4x-19/8x=21$
$- \frac{17}{8} x = 21$ $-17/8x=21$
$x = - \frac{168}{17}$ $x=-168/17$
so
$y = \frac{1}{4} \cdot (- \frac{168}{17}) - 14 = - \frac{280}{17}$ $y=1/4*(-168/17)-14=-280/17$

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Which method do you use to solve the system of equations $y = \frac{1}{4} x - 14$ $y=1/4x-14$ and $y = \frac{19}{8} x + 7$ $y=19/8x+7$ ?

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Explanation:

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Which method do you use to solve the system of equations y=14x−14y=1/4x-14 and y=198x+7y=19/8x+7?

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Explanation:

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Which method do you use to solve the system of equations $y = \frac{1}{4} x - 14$ $y=1/4x-14$ and $y = \frac{19}{8} x + 7$ $y=19/8x+7$ ?