Why can't you have zero to the power of zero?

2 Answers
Feb 26, 2015

This is a really good question. In general, and in most situations, mathematicians define 0^0 = 1.

But that is the short answer. This question has been debated since the time of Euler (i.e. hundreds of years.)

We know that any nonzero number raised to the 0 power equals 1
n^0 = 1

And that zero raised to a nonzero number equals 0
0^n = 0

Sometime 0^0 is defined as indeterminate, that is in some cases it seems to be equal to 1 and others 0.

Two source I used are:
http://mathforum.org/dr.math/faq/faq.0.to.0.power.html

https://www.khanacademy.org/math/cc-seventh-grade-math/cc-7th-negative-numbers-multiply-and-divide/cc-7th-exponents-negative-base/v/powers-of-zero

Mar 9, 2015

Well, you kind of could have 0^0. In general, mathematicians leave 0^0 undefined. There are 3 considerations that might lead someone to set a definition for 0^0.
The problem (if it is a problem) is that they don't agree on what the definition should be.

Consideration 1:
For any number p other than 0, we have p^0=1.

This is actually a definition of what the zero exponent mean. It's a definition chosen for good reasons. (And it doesn't "break" arithmetic.)

Here's one of the good reasons: defining p^0 to be 1 lets us keep (and extend) the rules for working with exponents,
For example, (5^7)/(5^3)=5^4 This works by cancellation and also by the rule (p^n)/(p^m)=p^(n-m) for n>m.
So what about (5^8)/(5^8)?
Cancellation (reducing the fraction) gives us 1. We get to keep our "subtract the exponents" rule if we define 5^0 to be 1.
So, maybe we should use the same rule to define 0^0.
But . . .

Consideration 2
For any positive exponent, p, we have 0^p=0. (This is not a definition, but a fact we can prove.)
So if it's true for positive exponants, maybe we should extend it to the 0 exponent and define 0^0=0.

Consideration 3
We have looked at the expressions: x^0 and 0^x.
Now look at the expression x^x. Here's the graph of y=x^x:

graph{y=x^x [-1.307, 3.018, -0.06, 2.103]}

One of the things you may notice about this, is that when x is very close to 0 (but still positive), x^x is very close to 1.

In some fields in mathematics, this is good reason to define 0^0 to be 1.

Final notes
Definition is important and powerful, but cannot be used carelessly. I mentioned "breaking arithmetic". Any attempt to define division so that division by 0 is allowed will break some important part of arithmetic. Any attempt.

Last note: the definitions of x^(-n)=1/(x^n) and x^(1/n)= root(n)x are also motivated in part, by a desire to keep our familiar rules for working with exponents.