Why is the electron configuration of chromium #1s^2 2s^2 2p^6 3s^2 3p^6 3d^color(red)(5) 4s^color(red)(1)# instead of #1s^2 2s^2 2p^6 3s^2 3p^6 3d^color(red)(4) 4s^color(red)(2)#?

1 Answer
Aug 4, 2016

It's a combination of factors:

  • Less electrons paired in the same orbital
  • More electrons with parallel spins in separate orbitals
  • Pertinent valence orbitals NOT close enough in energy for electron pairing to be stabilized enough by large orbital size

DISCLAIMER: Long answer, but it's a complicated issue, so... :)

A lot of people want to say that it's because a "half-filled subshell" increases stability, which is a reason, but not necessarily the only reason. However, for chromium, it's the significant reason.

It's also worth mentioning that these reasons are after-the-fact; chromium doesn't know the reasons we come up with; the reasons just have to be, well, reasonable.

The reasons I can think of are:

  • Minimization of coulombic repulsion energy
  • Maximization of exchange energy
  • Lack of significant reduction of pairing energy overall in comparison to an atom with larger occupied orbitals

COULOMBIC REPULSION ENERGY

Coulombic repulsion energy is the increased energy due to opposite-spin electron pairing, in a context where there are only two electrons of nearly-degenerate energies.

So, for example...

#ul(uarr darr) " " ul(color(white)(uarr darr)) " " ul(color(white)(uarr darr))# is higher in energy than #ul(uarr color(white)(darr)) " " ul(darr color(white)(uarr)) " " ul(color(white)(uarr darr))#

To make it easier on us, we can crudely "measure" the repulsion energy with the symbol #Pi_c#. We'd just say that for every electron pair in the same orbital, it adds one #Pi_c# unit of destabilization.

When you have something like this with parallel electron spins...

#ul(uarr darr) " " ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr))#

It becomes important to incorporate the exchange energy.

EXCHANGE ENERGY

Exchange energy is the reduction in energy due to the number of parallel-spin electron pairs in different orbitals.

It's a quantum mechanical argument where the parallel-spin electrons can exchange with each other due to their indistinguishability (you can't tell for sure if it's electron 1 that's in orbital 1, or electron 2 that's in orbital 1, etc), reducing the energy of the configuration.

For example...

#ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(color(white)(uarr darr))# is lower in energy than #ul(uarr color(white)(darr)) " " ul(darr color(white)(uarr)) " " ul(color(white)(uarrdarr))#

To make it easier for us, a crude way to "measure" exchange energy is to say that it's equal to #Pi_e# for each pair that can exchange.

So for the first configuration above, it would be stabilized by #Pi_e# (#1harr2#), but the second configuration would have a #0Pi_e# stabilization (opposite spins; can't exchange).

PAIRING ENERGY

Pairing energy is just the combination of both the repulsion and exchange energy. We call it #Pi#, so:

#Pi = Pi_c + Pi_e#

Inorganic Chemistry, Miessler et al.

Basically, the pairing energy is:

  • higher when repulsion energy is high (i.e. many electrons paired), meaning pairing is unfavorable
  • lower when exchange energy is high (i.e. many electrons parallel and unpaired), meaning pairing is favorable

So, when it comes to putting it together for chromium... (#4s# and #3d# orbitals)

#ul(uarr color(white)(darr))#

#ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr))#

compared to

#ul(uarr darr)#

#ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(uarr color(white)(darr)) " " ul(color(white)(uarr darr))#

is more stable.

For simplicity, if we assume the #4s# and #3d# electrons aren't close enough in energy to be considered "nearly-degenerate":

  • The first configuration has #\mathbf(Pi = 10Pi_e)#.

(Exchanges: #1harr2, 1harr3, 1harr4, 1harr5, 2harr3, #
#2harr4, 2harr5, 3harr4, 3harr5, 4harr5#)

  • The second configuration has #\mathbf(Pi = Pi_c + 6Pi_e)#.

(Exchanges: #1harr2, 1harr3, 1harr4, 2harr3, 2harr4, 3harr4#)

Technically, they are about #"3.29 eV"# apart (Appendix B.9), which means it takes about #"3.29 V"# to transfer a single electron from the #3d# up to the #4s#.

We could also say that since the #3d# orbitals are lower in energy, transferring one electron to a lower-energy orbital is helpful anyways from a less quantitative perspective.

COMPLICATIONS DUE TO ORBITAL SIZE

Note that for example, #"W"# has a configuration of #[Xe] 5d^4 6s^2#, which seems to contradict the reasoning we had for #"Cr"#, since the pairing occurred in the higher-energy orbital.

But, we should also recognize that #5d# orbitals are larger than #3d# orbitals, which means the electron density can be more spread out for #"W"# than for #"Cr"#, thus reducing the pairing energy #Pi#.

That is, #Pi_"W" < Pi_"Cr"#.

Since a smaller pairing energy implies easier electron pairing, that is probably how it could be that #"W"# has a #[Xe] 5d^4 6s^2# configuration instead of #[Xe] 5s^5 6s^1#; its #5d# and #6s# orbitals are large enough to accommodate the extra electron density.

Indeed, the energy difference in #"W"# for the #5d# and #6s# orbitals is only about #"0.24 eV"# (Appendix B.9), which is quite easy to overcome simply by having larger orbitals that stabilize the pairing energy.