Question

Question #477c1

Answer 1

`NH_4^(+) + H_2O -> NH_3 + H_3O^+`
`Acid + Base -> Conj B + Conj A`

On the reactant side of the equation the Ammonium (`NH_4^+`) is the Acid as it is the hydrogen ion donor to the Water (`H_2O`) which is the Base as it receives the hydrogen ion.

On the product side the Hydronium (`H_3O^+`) is the Conjugate Acid as it is the hydrogen donor to the Conjugate Base Ammonia (`NH_3`) as it receives the hydrogen ion.

`NH_4^(+) -> NH_3`
`Acid -> Conj B`
The Ammonia (`NH_3`) is the Conjugate Base pair to the Acid Ammonium (`NH_4^+`) .

`H_2O -> H_3O^+`
`Base -> Conj A`

The Hydromium (`H_3O^+`) is the Conjugate Acid pair to the Base Water (`H_2O`).

I hope this was helpful.
SMARTERTEACHER