Question

What is the hybridization of PF5?

Answer 1

the hybridization of `PF_5` is `sp^3d` .

In `PF_5` , the valence electrons of phosphorus are 5.
and we take the oxidation state of halogens as 1.

So, for one F , electron is 1 and for `F_5` the no. of electrons is 5.

therefore, (from phosphorus and fluorine)

5-5=0 electrons = 0 lone pairs.

there are 5 sigma bonds in this compound.

So, 5 sigma bonds + 0 lone pairs = 5. `->` `sp^3d`

hence , the hybridization of this compound is `sp^3d` .

Note:-

2 has sp hybridization.
3 has `sp^2` hybridization.
4 has `sp^3` hybridization.
5 has `sp^3d` hybridization.
6 has `sp^3d^2`