Question #7321f

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Media Owl · Meave60
Feb 6, 2015

Balanced Equation:

#"2KNO"_3 + "10Na" rarr "K"_2"O" + "5Na"_2"O" + "N"_2"#

Mole ratio of #"KNO"_3"# to #"Na"# = #"2 moles KNO3"/"10 moles Na"#. Your teacher may want you to reduce this to #1/5#.

This is a redox (oxidation-reduction) reaction. The Na was oxidized from 0 in Na to +1 in #"Na"_2"O"#, and the N was reduced from +5 in #"KNO"_3"# to 0 in #"N"_2#. The oxidation numbers of the other elements did not change.

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