How do you find the slope of a line perpendicular to $5x-2y=-1$ ?

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Answer 1 · 2015-04-01T23:44:58

Remember that given a slope, $m$ , the slope perpendicular to it is $-1/m$ (the negative of its inverse).

Re-write the given equation $5x-2y= -1$ in slope-point form:
$y=5/2x +1/2$

The slope of the given equation is $5/2$
and the slope of a line perpendicular to it is $-2/5$

Answer 2 · 2015-04-01T23:46:43

The slope is: $(-2/5)$

Perpendicular lines' slopes are negative reciprocals.

$y = (5x+1)/2$

The slope of line $y$ is: $5/2$

So $m * (5/2) = -1$

We need to find $m$ to find the slope of the perpendicular line.

$m = (-2/5)$

How do you find the slope of a line perpendicular to 5x-2y=-15x-2y=-1?