What is the period for $y = 2 tan (3 π (x) + 4)$ $y=2 tan(3pi(x) +4)$ ?

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What is the period for $y = 2 tan (3 π (x) + 4)$ $y=2 tan(3pi(x) +4)$ ?

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Answer 1 · 2015-04-19T11:08:08

I believe $3 π (x)$ $3\pi(x)$ means $3 π x$ $3\pix$ , this notation doesn't make any other sense to me.
If so, the period must be $\frac{1}{3}$ $1/3$ .

We know that the period of $tan (θ)$ $tan(\theta)$ is $π$ $\pi$ , and we know that adding a constant and multiply by a constant outside doesn't change the period.
So it must be the same period of $tan (3 π x)$ $tan(3\pix)$ , which is trivially $\frac{1}{3}$ $1/3$

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What is the period for $y = 2 tan (3 π (x) + 4)$ $y=2 tan(3pi(x) +4)$ ?

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What is the period for y=2 tan(3pi(x) +4)y=2tan(3π(x)+4)y=2 tan(3pi(x) +4)?

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What is the period for $y = 2 tan (3 π (x) + 4)$ $y=2 tan(3pi(x) +4)$ ?