How do you prove #(cos^2x) / (sin^2x) * (1) / cos^2x = csc^2x#?

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Answer 1 · 2015-04-19T18:34:03

Know that:

#1/sin^2x=csc^2x#

So...

#LHS=cos^2x/sin^2x *1/cos^2x=1/sin^2x=csc^2x=RHS#

Answer 2 · 2015-04-19T18:35:49

On the left hand side the #cos^2x# cancels out and you are
left with

#1/sin^2x#

Now #cscx=1/sinx#

So

#1/sin^2x=csc^2x#