Question #90a50

1 Answer
Alexander L.
Apr 22, 2015

The graph in essence is not a linear graph.

Hence, we would want to transform the graph with a sort of operator.

T=AL^c
LogT=Log(AL^c)
LogT=LogA+LogL^c
LogT=LogA+cLogL

You can now recognize this as Y=C+MX

Y=LogT
C=LogA
M=c
X=LogL

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