Question

Question #adabe

Answer 1

This question requires some chain rule action!
Let's begin by reminding ourselves of some basic derivative rules:
`d/dx e^x = e^x`
`d/dx cos(x) = -sin(x)`

Putting this all together, we get:
`d/dx e^(cos(6x)) = e^(cos(6x)) * -sin(6x) * 6 = -6sin(6x)e^(cos(6x))`