What is the axis of symmetry of the graph of y=x^2-3x+9?

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What is the axis of symmetry of the graph of y=x^2-3x+9?

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Answer 1 · 2015-05-08T19:29:18

$x = \frac{3}{2}$ $x=3/2$

the axis of symmetry of a parabola $y = a x^{2} + b x + c$ $y=ax^2+bx+c$ is given by $x = - \frac{b}{2} a$ $x=-b/2a$ (it's a vertical line), because $- \frac{b}{2} a$ $-b/2a$ is the $x$ $x$ of vertex of the parabola, and you know the axis is vertical and passes through the vertex, so you're done: $x = - (- \frac{3}{2}) \Rightarrow x = \frac{3}{2}$ $x=-(-3/2) => x=3/2$

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What is the axis of symmetry of the graph of y=x^2-3x+9?

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