How do you write the quadratic in vertex form given $x^{2} - 7 x + 9$ $x^2-7x + 9$ ?

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Answer 1 · 2015-05-15T01:07:32

$(- \frac{b}{2 a}) = \frac{7}{2}$ $(-b/(2a)) = 7/2$

$f (- \frac{b}{2 a}) = \frac{49}{4} - \frac{49}{2} + 9 = - \frac{49}{4} + 9 = - \frac{13}{4}$ $f(-b/(2a)) = 49/4 - 49/2 + 9 = -49/4 + 9 = -13/4$

Factored form: $f (x) = {(x - \frac{7}{2})}^{2} - \frac{13}{4}$ $f(x) = (x - 7/2)^2 - 13/4$

Check. Develop $f (x) = x^{2} - 7 x + \frac{49}{4} - \frac{13}{4} = x^{2} - 7 x + 9$ $f(x) = x^2 - 7x + 49/4 - 13/4 =x^2 - 7x + 9$ . Correct

How do you write the quadratic in vertex form given x2−7x+9x^2-7x + 9?