How do you factor #w^2- wx - 12x^2#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. May 17, 2015 Notice that #4 - 3 = 1# and #4xx3 = 12#. So #w^2-wx-12x^2 = (w-4x)(w+3x)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1745 views around the world You can reuse this answer Creative Commons License